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四、解答题：本题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤1R.【解折J0因为sm4生C=n号5-m(受-号)=cs号…1分所以由cosB十snA生C=0得cosB叶cosB=0,…2分所以2os号-s号-1=0，解得60s号=号或cos号B-1.…3分因为00，故as号、B=12…4分则号-B………3…5分(2)因为c:a=5:3,令c=5m(m>0),则a=3,……6分三角形面积公式可得号acsin B三2bX公，则15b=7ac=7X15m2,故b=7m,……8分由余弦定理可得b=a2十c2-2acc0sB,则49m=49m2,解得m=1,……9分从而a=3,c=5,b=7,故△ABC的周长为a十b十c=15.…10分18.【解析】(1)由S+1=2Sm十2(n∈N*)可得Sn=2Sm-1+2(n≥2，n∈N*),…1分两式相减得am+1=2an（n≥2，n∈N*).……2分又S2=2S十2=6，则a2=4,2=号=2.a12…3分所以+=2(n∈N*),…4分an所以数列{an}是首项为2，公比为2的等比数列，故n=2”.…5分人11(2)由(1)可得6=(2+1)(2*1t12主2+1'…8分故共前n项和T.-(2与2)十（五2）+叶（十2十），/11…10分化简可得T32十…12分19.【解析】(1)取AD的中点O,连结OP,OB,因为△PAD是边长为2的正三角形，所以OP=√3，OP⊥AD,①…2分又AB=BD=√7，所以OB⊥AD,且OB=√AB-OA2=√6，…3分于是OB2十OP2=9=PB2,从而OP⊥OB,②…4分D由①②得OP⊥面ABCD,…5分A而OPC面PAD,所以面PAD⊥面ABCD.…6分B(2)连接AC,设AC∩BD=E,则E为AC的中点，连结EQ,当PA∥面BDQ时，PA∥EQ,所以Q是PC的中点.…7分由(1)知，OA,OB、OP两两垂直，分别以OA、OB、OP所在直线为x轴、y轴、之轴建立空间直角坐标系如图，则B(0,√6,0)、c《-2n6,0.-10,0.P0.0③.由P.C标得Q(-1,）从而Di=16,0Dà-(0，)…8分n·DB=0,x+√6y=0,设n=(x,y,z)是面BDQ的法向量，则由{得6w%y十2=0，取y1,得n（√6,1，√2)…9分n.DQ=0,易知面ABD的一个法向量是1=(0,0,1)，…10分所以cos(n,n〉=日h号3…11分由图可知，二面角A一BD一Q的面角为纯角，故所求余弦值为-3…12分20.【解析I1)设满国E的焦距为20，由题设知-号，且当点M在湖圆E的短轴端点处时△MAB的面积最大，所以号·2a·=22,…2分即b=2√2，又2=十C2,从而解得a=2,b=c=√2，…3分椭圆E的方程为之十.(2)由(1)知，A(一2,0)，B(2,0),由题意可设直线1的方程为x=ty十1，因为，点D(1,0)在椭圆E内，直线L与E总相交，数学参考答案（附中版）一4

21.AR+AD=AC.证明：因为∠DCE=∠BC=∠A=90P,所以∠AC)+∠ACE=909=∠E+∠AC.所以∠AC)=∠∠A=∠EBC,在△ACD和△BEC中，{∠ACD=∠E,DC=CE.听以△ACD≌△BEC(AAS).所以AD=BC.所以AB+AD=AB+BC=AC22.(1)因为∠A+∠ABC+∠C+∠1DC=360°，∠A=∠C=90P.所以∠ABG+∠ADC=360°-90°-90°=180°.因为BE,DF分别分∠ABC和∠ADC,所以∠ABC=2∠1，∠ADG=2∠2.所以2∠1+2∠2=180°.所以21+∠2=号×180°=909(2)设多边形的边数为n,则(n-2)×180°=2×360°+360解得n=8.所以(8-2)×180°÷8=135°，即这个多边形的每个内角都是135°23.（1)因为ADLBC,BD=ED,所以AB=AE.所以∠D1E=2∠BME=20°，∠AED=90°-∠DAE=70°.因为EF垂H分AC,所以AE=CE.所以∠EAC=∠C,且∠AED=∠EAC+∠C=2∠C=70°.所以∠C=35.(2)因为△ABC的周长为18cm,AC=6em,听以AB+BG=18-6=12(cm).因为AE=CE.所以△ABB的周长=AB+B+AE=AH+BE EC=AB+BC=12(cm).24.（1)因为△ABC为等边三角形，所以∠ABG=60°.因为D为AC的中点，所以DB分∠ABC所以∠DC=30因为∠PDQ=120°，所以∠P=180°-120°-30°=30所以∠DBC=∠P.所以DB=DP(2)过点D作DBC交AB于点I.因为△ABC是等边三角形，AC=8,D是AC的中点，所以AD=CD=4,∠B=∠C=∠A=60°，BC=AC=8.因为DI∥BC,所以∠ADH=∠C=60°，∠AHD=∠B=60P.所以∠ADH=∠AHD=∠A=60所以△A)/是等边三角形，所以AD=HD=AH=4.所以IID=CD=BI=4.因为∠Q0P=∠H1DG=120P,所以∠QDH=∠PDC∠(OHDH=∠PDC,在△QDI和△PD中，HD=CD,∠(01110=∠C所以△ODH≌△PDC(ASA).所以HQ=CP:所以BQ+BP=BH+HQ+BP=4+BP+CP=1225.（1)选择方法证明如下因为AD分∠BAC,所以∠BAD=∠CMD,AB=AE.在△BAD和△EAD中，∠BAD=∠EAD,AD=AD.所以△BAD≌△AD(SAS).

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21.（本小题满分12分)某学校组织“中亚峰会”知识竞赛，有A,B两类问题，每位参加比赛的同学先在两类问题中选择一类并从中随机抽取一个问题回答.若回答错误，则该同学比赛结束：若回答正确，则从另一类问题中再随机抽取一个问题回答，无论回答正确与否，该同学比赛结束.A类问题中的每个问题回答正确得m(00,则学生甲应选择先回答哪类问题，使得累计得分的数学期望最大？并说明理由.22.(本小题满分12分)已知函数f(x)=e-2-alnx.(1)若函数f(x)在区间[1，+∞)上单调递增，求实数a的取值范围；(2)求证：当00.高二数学试题第6页（共6页）

22:08×令心无障碍162022~2023学年度六盟校下学期期末联考高二数学试卷参考答案1.CD(2X-3)=4D(X)=4×0.8=3.2.2.A因为f(x)=sin2x-f(0)x,所以f(x)=2cos2x-f(0),所以f(0)=-f(0)+2,故f(0)=1.3.A因为x2=7.505>6.635,所以变量x与y不独立，这个结论犯错误的概率不超过0.01.4.B因为C=C1=1Dm=28,所以r+1-56=(m-7)(m十8)=0，所以n=7或n=2-8(舍去).5.B(6x十3P的通项T1=C5(6x)()y-C63”x.所以按x的升幂排列3√x的第4项为T6+1=C3×63X36=22496.A由题意可得f(x)=e-2.令f(x)=e-2=-1,解得x=0.因为f(0)=1,所以点01到直线x十y十3=0的距离d一危-22.则AB两点之间的最短距离是22.7.B将2道必须相邻的工序捆绑在一起看作一个元素，加工顺序的种数为AAA?=144.8.D令=ln少，则=号-a,因为=4.5，=2.5，所以a=若-=-4=若+4，故第6个月的市场规模是e号+4=e万元.9.BC若所有的样本点都在一条直线上，建立的线性模型一定是直线，则|r=1.同时说明每个样本点的残差均为0，没有随机误差，则R2=1.10.AD由题意可得E(X)=6,D(X)=号则E)=28,D=60,11.AC由题意可知至少有1名女生的选法有C8一C种或C8C。十CC。十C种.12.CD令f)=e-2r-h(x+ef()=e-x-+e令g)=c-x-e则g)=e1十ae.业然当≥0时，g(x)≥0H成立，放gx)在0.十∞)止单调递增.因为g(0)=1-。>0,所以g(x)>0,即(x)>0在(0，十∞)上恒成立，f(x)在(0，十o)上单调递增，故当x>0时，f(x)>f0)=0,从而心=28+n(b十0)>2a+lna十e).令g(r)=r2+ln(x十e),x>0,易得g(x)在(0，十o)上单调递增，则>a.故选CD13.-1;y=(1-e)x因为f(x)=x-e,所以f(x)=1-e.令f(x)>0,得x∈(-o∞，0)；令f(x)<0,得x∈(0，十∞).所以f(x)在（一∞，0）上单调递增，在(0，十∞)上单调递减，故【高二数学·参考答案第1页（共5页）】·23-522B·f(x)mx=f(0)=-1.因为f(1)=1-e,f(1)=1-e,所以曲线y=f(x)在(1，f(1))处的切线方程为y-(1-e)=(1-e)(x-1),即y=(1-e)x.

大一轮复学案数学分层突破训练答案精解精析第一章集合与常用逻辑B表示植树优秀的学生，全班学生用全：7B荀子的名言表明积跬步未必能至千用语、不等式集U表示，则C,A表示除草合格的学生里，但要至千里必须积跬步，故“积跬步”CB表示植树合格的学生，设两个项目都是“至千里”的必要不充分条件第一节集合优秀的人数为x,两个项目都合格的人数8.Ap:lx+11≤2，解得-3≤x≤1，q:x1.BA={-1,1,2,4},B={x11x-11≤1}曰为y,作出Venn图，如图.由图可得20-x+≤a,因为p是g的充分不必要条件，B={x10≤x≤2，故A∩B={1,2}.x+30-x+y=45,化简得x=y+5,因为ymm所以[-3,1](-∞，a],即a≥1.2.A易得B=(-0,-1)U(2,+∞)，又A==10,所以xm=10+5=15.故选C.9.x<0,x2-3x+1<0（-2,3),∴.AUB=R,故选A10.(-0,1)解析由题意可知，不等式x23.B由题知，AnB={5,7,11},故AnB中-2x+m<0有实数解，元素的个数为3..△=4-4m>0,解得m<1,.实数m的取4.D由题可知，A={x|-31或a<0,则“a>1”5.D由ACB,得a≤-1.15.(-,-2)U0,2解析A={xI(x6.C由题意知a≠0，因为{1，a+b,a=+1)(x-6)≤0}={x|-1≤x≤6}是“上<1”的充分不必要条件，故A正{0,}，所以a6=0,则=-1,所以当B=⑦时，m-1>2m+1,即m<-2,满足确；根据存在量词命题的否定为全称量a=-1,b=1,所以b-a=2.故选C.B二A;当B≠O时，若B二A,则词命题，得“了x∈(0，+0)，nx=x-1”的7.B解法一（列举法）：由题意可知，集合A/m-1≤2m+1,5否定是“Hx∈(0，+∞)，lnx≠x-1”,故B的非空真子集有{0}，{1}，{2}，{0,1}，m-1≥-1，解得0≤m≤2正确；当x≥2且y≥2时，x2+y2≥4，当x210,2},11,2,共6个.2m+1≤6，+y2≥4时却不一定有x≥2且y≥2，如x解法二（公式法）：由题意可知，集合A的.5非空真子集的个数为23-2=6.综上，m<-2或0≤m≤2=5,y=0,因此“x≥2且y≥2”是“x2+y≥4”的充分不必要条件，故C错误；因为8.B因为A={0,2,4,5},B={-1,0,3},所16.BD对选项A,因为M={x|x<0},N=x“ab≠0”能推出“a≠0”，但“a≠0”不能以A-B={2,4,5},1x>0},MUN={x|x≠0≠Q,故A不成推出“ab≠0”，所以“a≠0”是“ab≠0”的又因为U={x∈Z1-22,B1x≥√2}，满足戴德金分割，此时M没有增函数”是“函数y=(a-1)x+a在R上={xlx2-2x-3<0,x∈R}={x|(x-3)(x+最大元素，N也没有最小元素，故D可能是减函数”的充分不必要条件1)<0}={x-12}n{xlx≤-1或x≥2.A“a∈M”→“aeN”,但“a∈N”"推不出前一项的值，故一定存在正整数N。,当n3}=[3,+0),故选项C正确；AU(C.B)“a∈M”,所以“a∈M”是“a∈N”的充分不>N。时，a>0,因此“{a,}为递增数列”是={yly>2}U{x|x≤-1或x≥3}=(-∞必要条件“存在正整数N。,当n>N。时，a,>0”的充-1]U(2,+∞)，故选项D不正确.故分条件3.CD至少有一个实数x,使x2+1=0是存选AC.在量词命题，但是是假命题，所以A不正②必要性：{a}为公差不为0的无穷11.[1,+0)解析集合A={x|0N。时，a,>0,-10}={xx>题，所以B不正确；3xeR,使-+4≤则{a,}为递增数列.-m},又(AUB)CC,∴.-m≤-1，解得m因此“{a,}为递增数列”是“存在正整数≥1实数m的取值范围是[1，+0).0是存在量词命题，当x=分时，+号N。,当n>N时，a.>0”的必要条件12.B根据题意，作出Venn图，如图：≤0成立，所以C正确；3x∈R,使x2+2x+综上，“{a,}为递增数列”是“存在正整数1=0是存在量词命题，当x=-1时，等式N,当>N。时，a>0”的充分必要条件成立，所以D正确14f(x)=sinx,x∈[0,2]（答案不唯一）4.A由a2>a,得a>1或a<0,则“a>1”是解析根据函数单调性的概念，只要找“a2>a”的充分不必要条件.到一个定义域为[0,2]的不单调函数，满满足M∩(CnN)=O,即M二N足在定义域内有唯一的最小值点，且5.B若直线m⊥面a,直线nC面B,ax13.C由x2-4x-5<0,解得-1受},0

基础题与中考新考法·七年级·上·数学1.5有理数的乘方为122500.1.5.1乘方12.9【解析】由题意可得a-2=0,b+3=0,所第1课时有理数的乘方以a=2,b=-3,所以b=(-3)2=91.A13.解：原式=-2023×2023+3×202320234-2023×202342.1(3)【解析】根据乘方的概念可知-（-2023+3)×20234(1-2023)×20234)的3次幂应写成（一子(--2020-2022易错点拔1010负数的乘方，在书写时一定要把整1011个负数用小括号括起来，(-a)”与-a”是14.解：(1)<，<，>，>，>；不相同的，(-a)”表示(-a)·（-a)·…【解法提示】因为12=1,2=2，所以12<2；(-a),-a”表示-(a·a·…·a)因为23=8,32=9，所以23<32；因为34=81，同步课43=64,所以34>43；因为45=1024,54=625，2.22,4,-(2×2×2×2)所以45>54；因为56=15625,65=7776，所以3.D4.B分56>6.5.1-15.2-15.3-1;-1;1;-1练(2)当n≤2时，n<(n+1)";6.解：(1)216；(2)0；(3)0.25；(4)256；当n≥3时，n>(n+l)";第(56(6号(3)因为2023>3，章7.D所以20232024>202420238.解：第一次转发后接收到短信的人数为所以-20232024<-20242023」2个，15.解：(1)：【解法提示】由题图可得，部分①第二次转发后接收到短信的人数为22个，第三次转发后接收到短信的人数为21.11的面积是4，部分②的面积是4×416？个，…所以当转发完4次后，接收到这条短信的人部分③的面积是↓×1-1y.,阴影部分的面16464数为2+22+23+24=30（人）19.B【解析】m个3相乘可记为3m,n个2相积=部分③的面积=64加可记为2n,所以原式=3m+2n(2)333，,311+…十10.C【解析】A.(-2)3=-8,（-3)2=9,不符4T166449s1、11-4+(416)+合题意；B.(-2)3=-8,2=8,不符合题意；11、C.(-2)3=-8,-23=-8,符合题意；D.(-2)4=16,-24=-16,不符合题意16.C【解析】由题意可知，7×7×7×7×7×711.122500【解析】由表中数据可得，底数的=76小数点向左（右）移动一位，方数小数点第2课时有理数的混合运算向左（右）移动两位，所以3502的值1.D2.C3.A14万唯七年级QQ交流群：688570199

y/2sin6x+孕y=h0:y=t118.(1)如图所示：作AB中点O,连接OC,OA,B:AA=AB,∠BAA=60°，DABA是等边三角形，∴AB⊥OA又：C4=4,AB=25,CB=27,满足CA2+AB2=CB2,即有A,B,⊥AC,而AB∥AB,所以AB⊥AC,OA∩AC=A,OA,ACc面AOC,.:AB⊥面A,OC,而OCc面AOC,所以AB⊥OC,又因为O是AB中点，所以CA=CB(2)若CA=4,则0C=√4-52=3，易知04=3，以点O为原点，分别以OA,OA方向为x,y轴，以过点O竖直向上的直线为z轴建立空间直角坐标系，如图所示：

1.Which of the following companies rates highest?A.Allied.B.American Van Lines.C.International Van Lines.D.North American Moving Services.2.What is the advantage of American Van Lines?A.It gives pricing information online.B.It is experienced in packing expensive items.C.It has moving containers for interstate moves.D.It guarantees the lowest price of the same service.3.What do the four companies have in common according to the text?A.They feature highly skilled movers.B.They have over 80 years of experience.C.They can provide moving services nationwideD.They can offer services for customized packing.BIn 2014,Mahoney performed an act of kindness as part of a Facebook challenge.She picked a79-year-old senior named Wagner,who regularly gave back to the community.Mahoney wanted toknow Wagner better,so they spent a day together,picking up groceries and getting their nails done."It was the first time in years that someone had made a day about her,"says Mahoney.Their shared experience got Mahoney thinking.How many other seniors might benefit fromdedicated attention?She came up with a plan:find local seniors with long-time dreams and work tofulfill their wishes.She named the new charity:We Are Young,or WAY for short.Seniors can nominate (themselves or be nominated by someone else;wishes are thenassessed by a community committee that looks at factors such as age-related physical barriers,socialisolation and financial need.Melanie nominated her husband,78-year-old Victor,to go rockhounding,a hobby he'd given upwhen it became too physically difficult to access the bay where he hunted for geodes ()Theteam at WAY hired a boat for him and his son so they could reach the bay and search out geodes onthe beach."Now,Victor has regained his self-confidence and is willing to take on new challenges.Wewant to show that anything is possible with the support of others,"says Mahoney.Up to now,WAY has delivered on 41 dreams,ranging from a helicopter trip over a childhoodblueberry-picking spot to travelling to Toronto to watch a Blue Jays game.While her charity operatesonly in Nova Scotia,Mahoney has her own dream.Each WAY wish is recorded on video,and shewants people watching to be inspired to fulfill a wish for a senior in their own community."We wantto create a national movement that shifts how we as a society view,value and support seniors,"saysMahoney."That is the impact we're trying to create."英语试题第3页共10页

等号成立综上所述，8a十c的最大值为2(方法二)由不等式f(x)≥2ax+b的解集为R,知不等式ax2+(b-2a)x十c-b≥0恒成立，a>0则△=(b-2a)2-4a(c-b)≤0即/Q>0b2≤4ac-4a2624c一4令后则产28+528+2(-D+20-D+94(t-1)当t=1时8a2+e=0:624(t-1)44=1当1时群+6-1+号2+：当且仅当-1=，27即=46=a时：等号成立签上所述·的最大值为分11.【解题分析】(1)f(x)+f(-x)=2x2+2,f(x)-f(-x)=-2(a+1)x.当a=-1时，f(x)=f(一x),此时函数f(x)为偶函数；当a≠一1时，函数f(x)为非奇非偶函数，(2)因为a=0,所以f(x)=x2-x+1.因为对Hx1,x2∈[t,t+1],都有|f(x1)一f(x2)<6恒成立，所以[f(x)]max-[f(x)]min<6.当+1≤，即≤-号时，[fx)]x=2-十1，f(x)m=(1+I)2-(+1)+1,所以-21<6，所以>-3，放-61≤-2当合<0时，[fx)]=f)=-1<子，[fx]m=f分)=是，所以[f(x)]-[fx)]m<6,故-号<1≤0：当0<4≤2时，[f(x]=f+1)=P+4+1≤，[fx)]=f号)=，所以Lfx)]f)]m<,故0<1≤2：当>2时，[f(x)]m=2-t+1,[fx)]nx=(t+1)2-(t+1)+1,[f(x)]-[f(x)]m<6,可得21<6，故2<1<3.综上所述，一3

学方法报湘教七年级B国内统一连续出版物号：CN14-0706/(F)数学周刊参考答案第5期2023年11月07日第13期参考答案第1课时数据的收集与抽样第5章数据的收集与统计图(5.1~5.2)同步诊断自主学：抽样调查一、选择题课堂探究：例140%例2C1.C2.D3.B4.B5.C6.C即学即练：1.D2.C3.D4.D5.B6.D二、填空题7.全面调查7.折线8.全面调查9.样本选取不合理8.解：总体是该市七年级学生的视力状况；个体是该市每10.A酒店营业额逐月稳定上升名七年级学生的视力状况：样本是抽取的1000名七年级学生11.80012.30的视力状况：样本容量是1000.三、解答题9.(1)抽样调查.(2)抽样调查.(3)全面调查.13.解：(1)采用的是抽样调查.第2课时统计图(2)总体：七年级400名学生的视力情况；自主学：折线扇形条形条形扇形折线样本：抽取的80名学生的视力情况；课堂探究：(1)抽查的样本总人数为14÷28%=50，等级B的个体：该校七年级每一名学生的视力情况：人数为50×40%=20，补全条形统计图略样本容量：80.(2)等级D所在扇形的圆心角的度数为360°×4=28.8°14.(1)抽样调查300即学即练：1.B2.A3.D4.D5.A6.60°(2)喜欢收听易中天《品三国》的学生最多，7.乙3620甲15.解：(1)选择交通监督的人数是12+15+13+14=54（人）.8.解：(1)调查的总人数为20÷40%=50，则b=50×8%=4,a=选择交通监督的人数占调查人数的百分比是，54××100%=20050-20-16-4=10.27%.2360×072扇形统计图中交通监督所在扇形的圆心角度数是360°×答：表示“比较熟练”的扇形部分的圆心角的度数为72°、27%=97.2°.9.解：(1)国庆期间物华超市4日的营业额最高，蓝天超市(2)D班选择环境保护的学生人数是200×30%-15-14-16=1日的营业额最低15(人).补全折线统计图如图所示：(2)蓝天超市3日、7日的营业额超过了物华超市，6日的营个人数（人）业额和物华超市最接近.16----·一环境保护15·交通监督14(3)蓝天超市国庆节期间的营业额整体呈现先升后降的1312趋势；物华超市国庆节期间的营业额整体呈现先升后降再升最后降的趋势0A BC D班级

必修一UNIT1同步评估参考答案及部分解析参考答案1-5 BBAAC6-10 ACBAC11-15 BCBAC16-20 CBACA21-25 BCABA26-30 DDBCA31-35 DCCAD36-40 GEFAC41-45 CADAC46-50 BDABC51-55 CDADB56.which57.interested58.and59.took60.up61.countries62.supporting63.to travel64.myself65.deeply写作（划线部分为精彩表达）第一节One possible version:NoticeWe are pleased to say that our English Club is now looking for new members!The recruitment

3.No country has the right to dominate (v.tocontrol or have a lot of influence over sb/sth,especially in an unpleasant way)global affairs,control the fate(命i运)of others or keepadvantages in development all to itself.5.掌握更多的单词和短语，你就会发现用英语4.It is no use complaining (v.to say that you are交流更容易了。(find it easier to do sth)annoyed,unhappy or not satisfied about sb/sth)Know more words and expressions,and youabout the mistakes.What we need to do now iswill find it easier to communicate in English.correct them.5.The new system is currently being tested in pigs,with plans to seek government approval (n.official permission)for human testing sometime®in the future.⑧Ⅱ.根据所给的汉语提示，用适当的短语完成下V.用括号内所给单词的适当形式填空。列句子。（每空一词）l.On behalf of(代表)the Students'Union,'d1.I had planned (plan)to go to Hainan for theSpring Festival this winter,but my husbandlike to put forward a proposal to save waterpreferred to stay at home.on our campus.2.During the past few days,Tony has received2.After careful consideration,James decided to(receive)a flood of emails from the audiencedo the experiment all over again(从头再来).telling him how his lecture has affected them.3.I'll never forget hearing this piece of music3.By about 6000 BC,people had discovered_for the first time(第一次).(discover)the best crops to grow and animals toraise.4.I haven't seen Mrs Brown since I left (leave)school,but I often think about her.4.For a hit show,profits can add up to5.When Wilson returned home from the hospital,计达)millions of dollars.his parents tried to find a way to deal with the5.In contrast to(和.对比)a profit ofdisaster that had happened (happen)to their$13 million last year,the company lostlives.$10 million this year.6.Mr Smith and Johnson were talking (talk)about something,so I didn't say hello to themwhen I passed by them⑧③Ⅲ.根据汉语意思以及括号中所给的提示翻译下7.I wanted to make dumplings but found I列句子。had run (run)out of flour,so I went out tobuy some.1.我过去每周至少去看一次电影。(used to)8.By the time her mom arrived home afterI used to go to the movies at least once a week.work,Jessica had prepared (prepare)dinner.2.到目前为止，该组织已经为那些受洪水影响的9.Three days passed when she realized that the人筹集了50多万元。(so far)parcel had been sent (send)to the wrongSo far,the organization has collected moreplace.than half a million yuan for those affected by10.It was the first time that Nancy had giventhe floods.(give)a speech before so many people,so she⑧felt very nervous.V.阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。3.根本没有完美的人。我的意思是，每个人都有自己的缺点。(there be no such thing as)My husband's recent knee replacement surgeryThere is no such thing as a perfect man.Whatgave us enough opportunity to 1.personallymean is that everyone has their own(personal)experience the kindness andshortcomings.sympathetic care of our health care 2.heroes4.当Bob走进宿舍时，发现Henry在翻他的包。(hero).My husband reflected on his 3.recovery(catch sb doing sth)(recover),"Every single person,from the doctorsWhen Bob entered the dormitory,he caughtto the nurses,treated me with sympathy,respectHenry going through his bag.and kindness."And I agreed!4.Taking_(take)onmultiple roles as needed,2

Part 3 /Using Language Assessing your ProgressCOLLECTIONS1.cross the whole country by railL.用括号内所给单词的适当形式填空。详情请参考2.take a boat ride out into the bay1.Astonished (astonish),I realized that the boys had also3.take a pleasant hike in a forest4.take a coach bound northrecognized what the gesture meant.5.the most awesome journey2.It was a misty (mist)morning,so I didn't drive to work.6.看到种类繁多的生物3.In that experiment,volunteers were asked for their案解析一7.向东南方驶去opinions about a series of advertisements(advertisement).8.持续…4.My father is one of the most famous9.继续下一段旅程photographers(photographer),and he has won many10.游览这个城市national prizes for his photos.11.take sb's breath away with its exceptional beauty5.Our language is filled with.idioms (idiom)whick may12.beautiful cobblestone streets③make no sense to you if you haven't learned them.13.古老的砖建筑14.蒙特利尔的红枫叶山根据汉语提示补全下列句子，每空一词。l5.be typical of.…1.Contrary to(与…相反)the16.a short distance awayexpectations of their parents,the children behaved17.a bunch of farmsbravely in the hiking18.in an urban area2.Lily sat down and proceededto详情请参考19.all in alltell(进而告诉)me about her skiing holiday20.have a few hours to kill3.In the TV interview,the coach owedthevictoryto_(把胜利归功于)the team spirit..4.Incontrastto(与…形成对比)案解析21.站在远处22.驶过23.有空做某事her elder brother,Mary is always considerate in her24.与…形成对比treatment of others.25.说英语有口音5.Many cars and trucks rolledby(驶过26.一个拥有绝妙风景和声音的城市gbut no one gave us a lift.本期报纸其他版块参考答案1版详情请TOPIC READING4版①对于那些想要品尝这座城市最美味菜肴的人来说，蒙特利尔举世闻名的美食界将是一个巨大详情请参考答案解析完形填空1-5 BDCAB 6-10 ADCBD的吸引力。11-15ACDBC答案解析②即使你没有计划，仅仅在风景优美的鹅卵石街道上漫步也是值得的。阅读理解1-4 CBDALISTENING PRACTICE阅读填空1-5 BCABC6-10 ABABA1-5 DGCBF11-15 BABAC16-20 ACBCA摩豆2版MIND MAP1.from Vancouver to Toronto详情请参考答案解析2.the massive mountains and forests of Canada3.took their breath away with its exceptional beauty4.bound for Jasper5.spectacular mountain peaks and forests and manydifferent creatures6.Canada's huge oil and gas drilling industry7.many shopping malls8.they travelled through the night9.a land of forests and lakes10.Lake HuronINTO THE TEXTSAB详情请参1.enjoying1.proceeded2.an2.astonished3.to take3.which答案解析4.where4.had moved5.its5.with6.creatures6.talking7.stops7.were8.to8.an9.truly9.themselves10.that10.happily2

第二节（满分25分） 阅读下面材料，根据其内容和所给段落开头语续写两段，使 之构成一篇完整的短文。 Mr Dawson was an old grouch,and everyone in town knew it.Kids knew not to go into his yard to pick a delicious apple. Old Dawson,they said,would come after you with his gun. One Friday,12-year-old Janet was going to stay all night with her friend Amy.They had to walk by Dawson's house on the way to Amy's house,but as they got close,Janet saw him sitting on his front porch and suggested they cross over to the other side of the street.Like most of the children,Janet was scared of the old man. Amy said not to worry.Mr Dawson wouldn't hurt anyone.

【答案】 I have some good news for you,Simon.Some volunteer volunteers from all over the world are needing for the Olympic Winter needed Games in Beijing.The following is some requirements you are should meet.To be A Olympic volunteer,you must have a good an command of Chinese and English.Since you have been learning Chinese in America,you have an advantage over others in lan- guage.Beside you are enthusiastic,optimistic and active,that Besides which satisfies the demands for volunteers well.You will definitely de-

19.(12分)如图，四棱锥P-ABCD中，底面ABCD是行四边形，AB=1,BC=2,∠ABC=60,PC⊥CD,M为棱PA的中点.(1)证明：PA⊥CD;A0-09(2)若PA1AC,二面角P-CD-A的大小为60°，求直线MD与面PCD所成角的正弦值，(乃)y.120.(12分)已知在面直角坐标系x0y中，抛物线C:)2=2px(p>0)的焦点为F,过点P(0,3)的直线l与C交于A,B两点，且tan∠PF0=3.(1)求C的标准方程；(2)已知E为x轴上的点，直线EA与C的另一个交点为M,直线EB与C的另一个交点为N,当直线MN的斜率为1时，求点E的坐标。y=-3X+3X年719%4X99X-22121.(12分)已知函数f(x)=e-ax-lnx-1.(1)当a=e-1时，求f(x)的单调区间；心7mtXN≥2.(2)若f(x)存在零点，求实数a的取值范围。x:e=mx)x-(e-0'Inx100Xn汁e)哦Xexes mxe'x)mxexthx feInxr alnee'x+元0exalne"=x+mx +hx.22.(12分)现有甲、乙两个不透明盒子，盒子装有2个红球和2个白球，乙盒子装有4个白球，这些球的大小、形状、质地完全相同，在一次球交换过程中，从甲盒子与乙盒子中各随机选择1个球进行交换，重复几次这样的交换过程后，甲盒子里装有红球的个数为X(1)求X2的概率分布及数学期望；(2)求P(X.=1).PlXn+60ED用1甲堂材4奇(四@x烟+和动+数收x②包②甲冰X()

【答案】1.of2.annoyed3.who/that 4.(should)be taught 5.which 6.Apparently 7.how 8.in 9.Whether 10.changing

less compared with migratory(迁移的)animals such as birds. "It's an insight into how they build up their picture of space, adds Richard Holland,a biologist at Bangor University who studies bird navigation. There were already indications that dogs-like many ani- mals,and maybe even humans-can sense Earth's magnetic field.In 2013,Hynek Burda,a sensory ecologist at the Czech U- niversity of Life Sciences Prague who has worked on magnetic re ception for 3 decades,and his colleagues showed dogs tend to o- rient themselves north-south while excreting ()Because this behavior is involved in marking and recognizing field,Burda reasoned the line-up helps dogs figure out the location relative e to other spots.But fixed line-up isn't the same thing as navigation.

答案：61.cools62.Unluckily63.to make64.named 65.keeping 66.was forced 67.which 68.himself 69.it 70.the

【答案】l.criminal2.with3.be converted4.frightening 5.trying 6.simplified 7.sounds 8.making 9.variety 10.since

will be rude later on. Once infected,we are more aggressive, less creative and worse at our jobs.The only way out is to make a conscious decision to do so.We must have the courage to call it out,face to face.We must say,"Just stop.For Winston,that would have meant approaching the woman,telling her that her conversation was frustrating other passengers and politely asking her to speak more quietly or make the call at another time. The anger we feel at the rude behavior of a stranger can drive us to do out-of-place things.Research discovered that the acts of revenge (people had taken ranged from the ridicu- lous to the disturbing.Winston did shine a spotlight on the woman's behavior-but in a way that shamed her. When we see rudeness occur in public places,we e must step

tower struck two when she arrived. (Text 3) W:Do you have something to write with?How am I supposed to sign my name?Can I use a pencil? M:No,we lost our electronic pen.It doesn't matter,though. You can use your finger to sign right on the screen. (Text 4) M:You look sad.What's the matter with you? W:I went hiking yesterday.The mountains and the weather re- minded me of my hometown. M:I'm sorry to hear that.Why not give your family a call? (Text 5) M:I didn't see you last night at the office.Are you OK?

所以sin∠ADC=√3sinaP(X2)=所以sin(-)=5sina器品PX)是-司6所所以X的分布列为所以2c0s+2 sin a3sin a.123所以EX)=0X克+1×是+2×最3X立因为0

【解标】对于A,设P(x,y)(z<0),则-b(后-，国为A(-a,0),A:(a,0),直线PA1与PA:的斜率之yyy2 62积等于3，所以%·kp4,=。·’。=”a-=3,得离心率e√1+名=2，=2,故A错误；对于B,因为e=后=2，所以c=2a,而P为双南线左支上的一点，根据双由线的定义可得1PF,一PF=2a又周为PF,⊥PF,且SAeg,=3,所以SAe-号PF·PF=3,则PF·PF,=6,由PF,P+IPF,(2c)2,可得(PF1-|PF21)2+21PF1l·1PF21=4c2,即4a2+12-16a2,解得a=1,故B错误；对于C,如图，设PF,的中，点为O1,0为原点，则00，为△PFF,的中位线，所以00，=2PFl=2PF+2a)-2PF,十a,时以线授PF,为直径的国，园心为0，半径=2PF,以线段AA:为直径的圆，国心为0，1半径=a,所以00-PF,十a=7,+r,故两个国外切，故C正确；对于D,因为点P,到C的-条浙近线的距离为√5，所以b=√3，又由前面的推理可知=3，所以a=1,故C的实轴长为2a=2,故D错误.012.已知抛物线y2=16x,过点M(2,0)的直线交抛物线于A,B两点，F为抛物线的焦点，若|AF|=12,O为坐标原点，则四边形OAFB的面积是展个一出A.20√2B.10√2C.52D.5V22家】【答案】A【解析】抛物线y2=16x的准线方程为x=一4，设A(x1,y1),B(x2,y2),由抛物线的定义可知，x1十4=12，得x1=8,yi=16X8,由抛物线的对称性，不坊令y=8巨，设直线AB的方程为x=my十2，由区=m+2”得y2=16x,y-16my-32=0,6>0,则1-=-32，片以2=-2，E,四边形0AFB的面叔5=20F1·y,-yl=名×4×10区=20E*数学中有许多寓意美好的曲线，曲线C:(x2十y2)3=4x2y2被称为“四叶玫瑰线”（如1v单图所示)给出下列三个结论：出灰因①曲线C关于直线y=x对称；②曲线C上任意一点到原点的距离都不超过1；○③存在一个以原点为中心、边长为√2的正方形，使曲线C在此正方形区域内（含边界）】其中，正确结论的序号是A.①②B.②③c.①③D.①②③【答案】A【解析】对于①，用(y,x)替换方程中的(x,y),方程形式不变，所以曲线C关于直线y=x对称，故①正确；对于。95·