2023年T8联盟高考仿真模拟卷历史试题（一）参考答案及多维细目表题号2面反映社会控制的松弛，故选A项。材料没有反答案D映法治理念强化、门第观念淡化和社会流动增强，没有对比关系，所以B,C、D项错误。题号1112131415165.【答案C答案BCA0【解析】本题考查清朝的统治政策。清朝人关后1.【答案B对儒家文化传统的传承和重视实质是构建思想【解析】本题考查华夏认同。西周时期楚国国君文化上的统治基础，即统治的合法性，梅建政治自称“蛮夷”，到“使人献天子”，再到“观兵于周认同，故选C项。保存历史文献、倡导经学研究疆，问九鼎之轻重”，其变化过程实质是对中原华和弘扬孔孟之道都是次要目的，故A、B、D错误。6.【答案】C夏礼仪文化的逐渐认同，故选B项。楚国国力强盛是问鼎中原的基础，不是整个材料所反映变化【解析】本题考查中国近代民族资本主义的发展。的本质原因，A项错误。楚国中原交往密切是表大生纱厂在筹办过程中资金募集困难，没有体现面联系，不涉及实质，C项错误。西周礼乐制度其发展过程艰难，故A项错误。大生纱厂虽然有崩坏说法错误，礼乐崩坏在春秋战国时期，D项官机折旧和地方公款作为部分资金，但是它不是错误。官督商办，面是股份制的民族资本主义企业，故B2.【答案B项错误。募集资本困难并不能说明民间资本赢【解析本题考查西汉重农抑商政策。盐铁官营弱，故D项错误。大生纱厂的募资困雅是多种因素造成的，是半殖民地半封建社会环境造成的，政策的初衷是民众出钱，官府提供工具，组织生故C项正确。产后朝廷再统一收购销售，抑制豪强地主的同时7.【答案D增加财政收入，故A项错误。材料没有反映出对中小商人利益的打击，故C项错误。盐铁官多为【解析】本题考查清末东北改革。从材料可知，清富商担任体现的是盐铁官营的官员构成，但这不末新政东北改革中军政府被行省取代，中央集权加强，谘议局和及府州县议事会有一定近代民主能说明“士农工商”的社会地位结构改变，故D项色彩，故排除A、B项。中体西用是以中国传统错误。盐铁官营实际是国家参与盐铁的生产与纲常伦理指导改革，向西方学，材料体现的是销售，是国家对工商业经济的部分控制，影响到了工商业结构，故B项正确。中西制度杂糅，故C错误。D项体现了清末新政3.【答案D东北制度改革的目的，正确。8.【答案】A【解析本题考查唐代的货币政策。唐玄宗须布【解析】本题考查全面抗战前夕党的政策调整。法令要求实物与货币通用，主要原因是以物易物材料中给予“一切精神劳动者”“工商业主”“政府交换的长期存在，及货币经济、商品经济并不发及革命团体工作积极努力的（不论出身）”以选举达，敏选D项。材料并未体现唐代赋税制度和货权，主要目的是调动他们的积极性，为抗日数国币原料的问题，重农抑商历代都长期施行，故A、奠定基础，故选A项。材料不是“三三制”具体体B、C项错误。4.【答案】A现，故B项错误。材料未体现党的工作中心的转移（依然在农村），故C项错误。材料的时间是【解析】本题考查宋代的社会关系。南宋法官判1936年，是在华北事变后，体现的是为抗日做准案中有大量关于婚姻、田宅、债负的诉讼，特别是备，不是反抗国民党统治，故D项错误。民事诉讼中关于田宅诉讼有50%以上说明土地9.【答案】A产权受到保护，婚姻财产关系受到法律保护，侧【解析】本题考查新中国成立后工业结构的变化。历史试题（一）参考答案第1页共5页

22Ddooumchekmdiand dovarety of other proTextM:I thought you cleaned this.My shirt still has red stains onoAs a cn has two sides,the smarphone also has its disad-fessional-level tasksW:I'm sorry,Sir.Our laundry service doesn't treat marks like23.Cheat bvantages.We spend too much tme cng with our friendsthat.You have to pay extra.watching videosand playing games thatecnt focus on ou:aready paid you20 for this load.Howuh太【分析studies,which makes us who are trapped in smartphones forget stain?100I suggest that we should use smarphones effectively and rea-:Alight then.By the way,this stain rom thedoW:Just $5the real life24.Dsonably.Do not play on the phoe for m than one hour contiof carrotsW:Vegetable noodles?Interesting.How'd that work for you?foeuously Do nowatc it ingaking.Don'trely on thesmartphone to kill time when boredM:Great,until I tried to eat them.They were really long,andlish li(三)they slipped right out of my chopsticks.Anyway,can you finish世this tonight?I have a Sunday dinner 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walk there M:A professor at MIT by the name of Jill Meanley has publicly经典stated there is no scientific or medical evidence for your elaims a-知的just within 5 minutesbout its benefits.Many schools also have banned the toy,saying表现Text 4W:So you have lived in Cambridge for thirty years.Were youit leads to a lack of focus in the classroom.27.DW:Well,that professor is allowed to have her opinion.元素elemborn there?M:No,I was born and brought up in a small town and onlyM:Fair enough.And who invented it?moved to Cambridge in my twenties when I got a job in the uni-W:Catherine Hettinger,a chemical engineer,was first believed【分to be its creator,but then we found that an IT professor named人versity.Scott McCoskery was the actual inventor.人28.Text 5M:Okay.Now it's time for a commercial break.More with Mar-W:Are the two boys your brothers?partM:Well,just this one is.The other is my cousin.garet Seabrook in a moment.D。W:The scenery on it is fantastic.Where did you take it?Text 10M:Hello,everybody.I'm 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drinks or any drinkmeW:Yes,of course.That would be nice.that contain chocolate before sleeping.Reading a bookoiW:Hi,this is Mary!Now that the midterms are over,some of us ing to a story,rather than musie,should help your n应Text 7are planning to go boating this weekend.You want to come along?lax.M:Sounds great,but I've never done it before.It would be better for schools to stay open ongers的hcoa1a临roukee时oae的pils can do homework before they get home.Anothe33fore finals.M:Yeah,what shall I have to bring then?half an hour later and end the school day half an hourW:In faet I've got everything ready.And I will drive theresIreally recommend that.1-5.BCBAC 6-10.CABCB 11-15.BCAAByou can bring what you want.It is convenient.16-20.CCABAM:I see.You are so kindhearted.W:So what would you say?21.B(解析：根据第二段“If you'veever walked outsi:rally foggy day where you cane very far you中a小oud如果你曾经在雾天走在外面，看不见限6M:Why not?W:Great!I'I give youac when find out when everyonewants to leave on 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·数学（人教B版）·参考答案及解析所以m≥0，13.解：“△ABC为锐角三角形”的充要条件是“a2+b2>即实数m的取值范围是[0，十∞).(15分)c2”12.解：(1)当m=1时，S={x0≤x≤2}，(3分)充分性证明：若a2十b2>c2,且a≤b≤c,则△ABC不得P∩S={x1≤x≤2).(6分)是直角三角形，(2)若选①：如果△ABC为钝角三角形，若“x∈P”是“x∈S”的充分不必要条件，则PS,则C>受，过B作AC的延长线的垂线，垂足为D1+m≥4，1+m>4,(如图1)，可得DB2+(CD+b)2=c2,则1-m<1,或1-m≤1，(10分)所以DB2+CD2+b+2b·CD=c2,1+m≥1-m,1+m≥1-m,即a2+b+2b·CD=c2,得m≥3，所以a2+b2c2”是“△ABC为锐角三角形”的充分若选②：条件(10分)若“x∈P”是“x∈S”的必要不充分条件，则SP,若1-m>1+m,即m<0时，S=必，满足条件，DD图1图2(1+m<4,1+m≤4，必要性证明：当△ABC为锐角时，过A作BC的垂当m≥0，则1-m≥1，或1-m>1,(10分)线，垂足为D(如图2)，m≥0，m≥0，c2=AD2+(a-CD)2空，得m=0,=AD2+CD2+a2-2a·CD综上，m≤0，=b2+a2-2a·CDc2”是“△ABC为锐角三角形”的必要若选③：条件若“x∈P”是“x∈S”的充要条件，综上所述，“a2十b>c2”是“△ABC为锐角三角形”1+m=4,的充要条件.(20分)则S=P,即(10分)1-m=1,m=3,此时方程无解，即实数m不存在.(15分)m=0,▣反馈意见有奖

E证明：延长BC交AD于F,连PF,(7分)设AD=3,由已知BE=2,CE=1,∠BEC=60°，由余弦定理知BC=V5(8分)，.BC⊥DE,∴.∠EBC=∠FBA=30,且∠FAB=120,∴.∠AFB=30,BF=V5,BF=BC(10分):PM=MC.BM IPF,且BM=PF(1I分).PFc面PAD,BMa面PAD∴.BM∥面PAD（12分).22.(12分)在面直角坐标系xoy中，点F1(-1,0),F2(1,0),1MF|+IMF2=4,点M的轨迹为C.(1)求C的方程：(2)设点P在直线x=1上，过点P的两条直线分别交C于A,B两点和E,F两点，若直线AB与直线EF的斜率和为0，证明：IPA·IPB|=IPE·IPFI(1)c=1,2a=42分)，b2=4-1=3即c的方程：b2=1,即+=1.(4分)(2)法一：设P(1,m)，设kAB=k,kEF=-k,则lAB:y=k(x-1)+m(5分)，联立直线1与椭圆C方程得：(3+4k2)x2+8k(m-k)x+4k2-8mk+4m2-12=0.(有联立就给分，6分)由8g4,Xaxa=-8mn2-业（7分）韦达定理：4十xB=8kkm,3+4k2IPAI.IPBI v1+k2lxA-11v1+k21xB-11=(1+k2)lxAXB-(xa+xB)+11=(1+k-m-业-4+1=1+k2到9分）3+4k2由已知可得：+园=把，4k2+8mk+4m2-123+4k23+4k2IPE·lPF|=√1+(-k)21xE-1·V1+(-k)2xF-1=(1+k2)lxεxF-(xE+xF)+1|=(1+s-2+1三（1+k的n分)即：IPA·IPBI=IPEI IPFI.(12分)高二数学学科试题第9页（共10页）

·数学（人教B版）·参考答案及解析的中点，面CCE⊥面CMN,面CC1E∩面作PE⊥AD于点E,由条件知E为AD的中点，连CMN-CE.接BE,又CE⊥MN,由题意知，PE⊥底面ABCD,∴.C,E⊥面CMN.则∠PBE=60°，∠CCE是直线CC1与面a所成角.(10分)设AB=2a,在Rt△C,MN中，C,E=GM,CN-1X1=2MN2则BE-5,器=m60-5,√2④所以PE=√I5a,.tan∠CCE=CE_2-2C1C24设BC的中点为F,连接EF,PF,则EF⊥BC,PF⊥BC,.sin∠CCE=3所以∠PFE为侧面PBC与底面ABCD所成二面角故直线CC,与面a所成角的正弦值为子，(15分)的面角，(15分)13.解：(1)因为底面ABCD为正方形，因为∠PEF=90°，EF=2a,所以CD⊥AD,所以PF=√I9a,又因为侧面PAD⊥底面ABCD,面PAD∩面故cos∠PFE=2a=2√19/19a19ABCD=AD,所以侧面PBC与底面ABCD所成二面角的面角所以CD⊥面PAD,因为CDC面PCD,的余弦值为21四(20分)19所以面PAD⊥面PCD.(8分)(2)如图，反馈意见有黄·38·

高一周测卷新教材·数学（人教A版）·高一同步周测卷/数学（十九）一、选择题确2+=1-+=合-合i,所以十1.C【解桥】由题得=牛-2+g-D-25=√（份）+(-)-号<2，故c错误，=1+102分i=号-吉所以：的邀部为-号·故法C25i,4=-是-合，所以·=(1+i)·2.B【解析】由题得e3i=cos3+isin3,其对应点为(cos3,sin3),由<30,所(-号-合)=-，故D正确，故选ABD,以点(cos3,sin3)在第二象限.故选B.8.ABC【解析】依题意，设1=a十bi(a,b∈R),则z23.B【解析】z=1+i+2十3i=3+4i,则之=3-4i.故选=a一bi,其中b≠0.则z1十之2=2a,为实数，A选项正B.确；之1一22=2bi,为纯虚数，B选项正确；之1·2=a2十4.D【解析】复数之=sin50°-icos50°=cos40°-,为实数，C选项正确会-+=。(a+bi)2a-bi (a-bi)(a+bi)isin40°=cos320°+isin320°，所以复数的辐角主值是320°.故选D.Q-:+2ai,当a≠甘时，不是纯虚数，D选项a2+b2之25.D【解析】(a+bi)(c+di)=(ac一bd)+(bc+ad)i,错误.故选ABC.是纯虚数的一个充要条件是ac一bd=0且abc三、填空题0,故选D.9-2-;【解折】：向量0成与复数-2对26.C【解析】设x=x十yi(x,y∈R),因为复数z满足1x-3+2i=|z,所以1(x-3)+(y+2)i川=|x+i川，应，立绕原点O按顺时针方向旋转于后再把模变即√x-3)2+(y+2)严=√2+，化简得6x-4y为原来的号倍得到向量O立，∴0立。对应的复数为13=0.故选C.二、选择题(-2D·[cos(-妥)+isin(-)]×号=(-3i)7.ABD【解析】设z2=a十bi(a、b为实数)，则z1z2=…(停-)-9-2(1-i)(a+bi)=i,即a十b+(b-a)i=i,所以10.3x【解析】不妨设复数之=x十yi,则|之-1十i训≤a+b=0,解得a=-合，6=是，所以=-名十b-a=1√3，即1(x-1)+(y+1)i≤3，则(x-1)2+(y+之i,故A正确；l=V+(-1=√E,lz=1)2≤3，其表示以(1，一1)为圆心且半径r=√5的圆的内部以及圆上的点，则这些点构成的图形的面积√(-)+（合丁-号，所以1=à故B正为π2=3π.。.11

2022年普通高中学业水选择性考试T8联盟·压轴卷（一）物理试题参考答案及双向细目表题号1231567891017.【答朵】B【解析】金属板始终带等量的异种电荷，A情误；设金属板答案D C B D CC B ACD BC BD AB的宽为工·板问距离为d,带心量为Q·则地容器心容C1.【答案】D的一品设转过角度为，测转过后，电容器电行【解析】X是轴239与铀238原子序数相同.A错误：X与怀239质量数相同，但质子数少2.因此中子数多2.B错C-山以2=C·mE.D错误Q沿顺时针方向转动·A、B错误：转动后，根据同向电流相互吸引，反向电流相互推斥可以判断，直线电流与线框相8.【答秦】ACD互吸引·因此悬线上的张力大于金属线框的重力，C正确：【解析】1=1s时刻波已传插到x=m处，因此波动周期为0.8s.1=1s时刻，r=0.6m处的质点已振动0.1s.A正确：D错误。3.【答案】B波化括的逃度=产=1m/,b错误1=5时=m处【解析】小球运动过程中，拉力与小球受到的弹性绳的弹力和重力的合力等大反向，山于受到的弹性绳的弹力大的质点已振动1.此质点运动的路程s=5×1-=4m,C正小不变，亚力不变·弹力与重力的夹加越来越小.因此小偷：x=0处的质点振动方程为y=20sin(2.5)cm,D正确球受到的弹性绳的弹力和重力的合力越来越人，拉力也9.【答案】3C【解析】带正电的粒子从静止开始仅在电场力作用下运越来越大，B正确动，电场力一定做正功，拉子的动能不断增大电势能不L.【答案】D【解析】由图可知，1=0，穿过线圈的随通量最大，此时无断减小，运动到的位置电势不断降低，如果八、B两点的感应电流·设线因的而积为S·线因转动角速度为w,则感点电荷带异种电荷，则C、D两点的点电荷也带异种电荷.则E、F两点一定等势.则粒子不可能运动到F点，由出电花最大值为。一架网时值为，=此可以判断，A、B两点的点电荷带同种电荷，且带正电C、D两点的点电荷带负电，A错误；G,川两点是等量异枚D正确.A,BC钻误种电荷连线垂直分线上的点，也势为零.书正确；E、F5.【答案】C【解析】山于在AB面的出射光线行，则在B面的人射连线上的场强从E点指向F点，因此粒子一定沿直线从光线也行，光线PO在AB面的人射角i=30°.设折射价E点运动到F点，C正确：带正电的拉了在E点由静止行为r.恨据题意及儿何关系有Ran1·cosrR.解得o放，一直做加速运动，电势能一有减小，D错误10.【答案】BD)=0.6.则sw=0.8因此折射率1=mr=1.6.c正【解析)根据题意可1=专1，一1)·八箭误小球压霸弹领前下落的高度A=,则弹领的最大压销量二-上别=片江小球与簧发触前一瞬同的速度大小v=,根据动量定理.11=2,得到小求何一次与弹箭接触过程弹舒弹力6.【答案】0【解析】由题意可知·P到挡板的距离为=：·小球向右对小球的冲量大小为1=1.2mg1C猎误：根据机城偏上3发射的小球与向（石偏下37发射出小球水半分能守恒定律，小球压缩弹簧过程中·弹该伏得的最人弹速度相同，因此它们从发射到打在挡板的时间相等，时性势能为F=m四X1.=k1.D正确间为/o37子，则背球打在指反位行的高1L.【答朵】16【解析】设金属作进爸场付速度为，则电健K闭合附：段为=sin371-'-(-n37-),示=心·根松能量分定律1.Q=,根LL.5.C喻X水物理试题)参答案第1贝北3项

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1、统编高中政治选择性必修2法律与生活第一单元民事权利与义务综合测试卷

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C.改变土地性质促进农业现代化发展D.都是对农村生产关系的完善和调整5.国家市场监督管理总局的统计信息显示，2012年至2021年，我国民营企业数量从1085.7万户增长到4457.5万户，10年间翻

3、苏教2019高考数学复：选择性必修第一册+第二册知识点清单汇编（实用必备！）

高二数学（二）试题(B)参考答案一、选择题：本大题共8小题，每小题5分，共40分，在每小题给出的四个选项中，只有一项是符合题目要求的，1-5 BABBC6—8DAA二、多项选择题：本大题共4个小题，每

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Zhai,the commander of the mission,was the first 59 (come)out of the capsule,waving his hand to the c

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因为ar≤生y,所以≥(a+c(生)户=a+c2…7分因为a+c=6,所以b2≥27，所以b≥3√3.………………8分因为b

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C.选文运用正面描写和侧面描写相结合的手法表现莎馨卡，如写她两颊消瘦，眼睛下面有黑晕，表明她在监牢受了苦；借叶戈尔之口从侧面表现她。D.选文描写了大量人物语言，这些语言有效表现了人物形象，其中一些语言

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教授笑了。教授就每天去教苗苗画画，从透视教起。但苗苗还是从不走出帘子一步，都是教授带着纸墨笔砚过去。但教授很高兴一他终于可以走进帘子了。大雪一次次飘落。苗苗学得很快，已经能画出很像样的百合花了。一老一